Equilibrium
Pg 318
#3, 5, 7, 8, 14, 15, 16, 19, 20, 21
#3 Kc = 2.4 x 10-4
#5. It will be the inverse K = 1 x 1030
#7. [N2O4] = 2.875 x 10-3 M
#8. c), b), a)
#14. [I2] = [Cl2] = 0.014 M
[ICl] = 0.138 M
#15. Initial [HF] = 0.1125 M
#16. [SO2] = 0.089 M
#19. Kc = 0.0025
#20. Kc = 50.5
#21. Kc = 1.2
Worksheet - Calculating [H3O+], [OH-], pH and pOH
#1 pH = 4.7 [OH-] = 5 x 10^-10 M
#2 pH = 8.3 [OH-] = 2 x 10^-6 M
#3 pH = 11.6 [H3O+] = 2.5 x 10^-12 M
#4 pH = 3.48 [H3O+] = 3.3 x 10^-4 M
#5 [H3O+] = 1 x 10^-3 M [OH-] = 1 x 10^-11 M
#6 pOH = 11.5 [H3O+] = 3.2 x 10^-3 M [OH-] = 3.2 x 10^-12 M
#7 pH = 12 [H3O+] = 10^-12 M [OH-] = 10^-2 M
#8 pH = 4.7 [H3O+] = 2 x 10^-5 M [OH-] = 5.01 x 10^-10 M
#9 pH = 10.7 pOH = 3.3 [H3O+] = 2 x 10^-11 M
#10 pH = 11.3 pOH = 2.7 [OH-] = 0.002 M
Acid Base equilibria
Pg 338 #1, 2, 7, 17 (find Ka), 22 Note: the Ka for acetic acid was given in class 1.8 x10-5, 24 (find Ka), 28 (find Kb), 33
#1 a) Cl - b) Co3 2- c) HSO4 - d) N2H4
#2 a) HNO3 b) H2O c) H3O+ d) H2CO3
#7 acidic
[H3O+] = 1.91 x10-5 M
[OH-] = 5.25 x 10-10 M
pOH = 9.28
#17 Ka = 9.99 x10-5 or 1.3 x 10-4, dissocation = 3.2%
#22 0.47%
#24 2.92 x 10-8
#28 Kb = 1.61 x 10-6
#33 pOH = 2.86, pH = 11.14
Acid-Base Equilibria Worksheet
#1. C
#2. D
#3. pH = 2.38
#4. pH = 4.68
#5. pH = 7.4 x 10-9
#6. C) Ka = 6.3 x 10-10
#7. 6.4
#8. Ka for HZ = 1 x 10-4, Ka for HX = 1 x 10-8 HZ is stronger
#9 H2CO3
#1. C
#2. D
#3. pH = 2.38
#4. pH = 4.68
#5. pH = 7.4 x 10-9
#6. C) Ka = 6.3 x 10-10
#7. 6.4
#8. Ka for HZ = 1 x 10-4, Ka for HX = 1 x 10-8 HZ is stronger
#9 H2CO3
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