Please refer to some of the last homework for November ( what was not covered in the last week of November but will be covered the first week of December).
Heat of
Neutralization
See molar heat of neutralization attachment below
for more practice.
Pg
195
#3, 7, 11 ( the moles of the acid and base are equal
in this problem so it does not matter which one you use to determine the molar
heat), 13
Answers
#3 41.987 kJ/mol
#7 30⁰C
#11 -58.576 kJ/mol
#13 -58.576 kJ/mol
Pg. 168
#2, 6, 16, 17 (incorporates gases!), 23, 24
Answers: # 2 a) -185.5 ⁰C
b) -189.36⁰C
c) -1188 kJ/mol
d) -6447 kJ/mol
# 6 a) -824.2 kJ/mol
b) graph - will post in class
c) 122 kJ
#16 a) The enthalpy change is 53.0 KJ/mol for the consumption of hydrogen and iodine.
b) 402.34 kJ
c) Ask teacher - see diagram in Chem Ans book
#17 114.82 kJ
#23 -57 kJ/mol
#24 a) 6CO2 + 6H2O →
C6H12O6 + 6O2 ∆H = 2803 kJ/mol
6CO2 + 6H2O + 2803 kJ → C6H12O6 + 6O2
b) graphs - will post in
class
Bond Energies and Energy
Balance Diagrams
Bond Energy
Section 1:
#2 -549 kJ
#3 O kJ
#4 -489 kJ
#5 -808 kJ
Section 2:
#9 -97 kJ
#10 -124 kJ
#11 -5657 kJ
Pg 160
#2, 3, 4 a and c, 5, 6 b, c, d
Answers
#2 Eco =1074 kJ/mol, which is close to the energy of
triple bond C≡O (1077 kJ/mol). Therefore, the bond is triple.
#3 It will be exothermic. The energy required to
break the A - A and B - B bonds is less than the energy released during the
formation of the two A - B bonds. Therefore, the energy balance produces a
negative enthalpy change.
#4 a) 436 kJ
c) -364 kJ
#5 The energy of the x - y bond is 65 kJ
#6 b) -4304 kJ
c) 992 kJ
d) -1980 kJ
Neutralization
See molar heat of neutralization attachment below
for more practice.
Pg
195
#3, 7, 11 ( the moles of the acid and base are equal
in this problem so it does not matter which one you use to determine the molar
heat), 13
Answers
#3 41.987 kJ/mol
#7 30⁰C
#11 -58.576 kJ/mol
#13 -58.576 kJ/mol
Pg. 168
#2, 6, 16, 17 (incorporates gases!), 23, 24
Answers: # 2 a) -185.5 ⁰C
b) -189.36⁰C
c) -1188 kJ/mol
d) -6447 kJ/mol
# 6 a) -824.2 kJ/mol
b) graph - will post in class
c) 122 kJ
#16 a) The enthalpy change is 53.0 KJ/mol for the consumption of hydrogen and iodine.
b) 402.34 kJ
c) Ask teacher - see diagram in Chem Ans book
#17 114.82 kJ
#23 -57 kJ/mol
#24 a) 6CO2 + 6H2O →
C6H12O6 + 6O2 ∆H = 2803 kJ/mol
6CO2 + 6H2O + 2803 kJ → C6H12O6 + 6O2
b) graphs - will post in
class
Bond Energies and Energy
Balance Diagrams
Bond Energy
Section 1:
#2 -549 kJ
#3 O kJ
#4 -489 kJ
#5 -808 kJ
Section 2:
#9 -97 kJ
#10 -124 kJ
#11 -5657 kJ
Pg 160
#2, 3, 4 a and c, 5, 6 b, c, d
Answers
#2 Eco =1074 kJ/mol, which is close to the energy of
triple bond C≡O (1077 kJ/mol). Therefore, the bond is triple.
#3 It will be exothermic. The energy required to
break the A - A and B - B bonds is less than the energy released during the
formation of the two A - B bonds. Therefore, the energy balance produces a
negative enthalpy change.
#4 a) 436 kJ
c) -364 kJ
#5 The energy of the x - y bond is 65 kJ
#6 b) -4304 kJ
c) 992 kJ
d) -1980 kJ
answers_to_hess.docx | |
File Size: | 15 kb |
File Type: | docx |
answers_to_bond_energy_worksheet.docx | |
File Size: | 70 kb |
File Type: | docx |
molarheatofneutralization.doc | |
File Size: | 30 kb |
File Type: | doc |
hesss_package_ans.pdf | |
File Size: | 1529 kb |
File Type: |